The answer is assess with the same value as mu, in which case this expression over here becomes zero, and we get the maximum. We get the peak of the Gaussian. We set x to the same value as mu, to 10, and the output is 0.2 approximately.
The answer is assess with the same value as mu, in which case this expression over here becomes zero, and we get the maximum. We get the peak of the Gaussian. We set x to the same value as mu, to 10, and the output is 0.2 approximately.