# 4 – 05 Implementing Constraints Solution V1

So, here’s the answer. Let me just re-transform this as it’s done over here. X1 minus x2 is now plus four, and x2 minus x1 is minus four. So, I have to add plus one over here, minus one over there, plus one in this diagonal element over here, and minus one over here. Let me just do this. These numbers L, the end transform the first number over here to two. We get a minus one for the off-diagonal elements, and a one over here. Now, we add four to the five, which gives us a nine, and a minus four to the zero gives minus four. So, this is where we are now.